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NEW QUESTION: 1
Which of the following correctly states the relationship between urgency, priority and impact?
A. Impact, priority and urgency are independent of each other
B. Impact should be based on urgency and priority
C. Priority should be based on impact and urgency
D. Urgency should be based on impact and priority
Answer: C
NEW QUESTION: 2
Windows identifies which application to open a file with by examining which of the following?
A. The file signature at the beginning of the file
B. The file Signature at the end of the file
C. The File extension
D. The file attributes
Answer: C
NEW QUESTION: 3
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2012-Server gehostet wird.
Die Datenbank enthält zwei Tabellen mit den folgenden Definitionen:
Globale Kunden geben Bestellungen aus mehreren Ländern auf.
Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM Kunden c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT (OrderAmount) AS OrderAmount
VON Bestellungen
GRUPPE NACH Kunden-ID, Versandland) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM Kunden c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANG () ÜBER (TEILUNG NACH Kunden-ID
ORDER BY COUNT (OrderAmount) DESC) AS Rnk
VON Bestellungen
GRUPPE NACH Kunden-ID, Versandland) AS o
ON c.CustomerID = o.CustomerID
Wobei o.Rnk = 1
C. SELECT CustomerID, CustomerName, ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName,
Ö. Lieferungsland,
RANG () ÜBER (TEILUNG NACH c. Kunden-ID
BESTELLUNG NACH o. OrderAmount DESC) AS Rnk
VOM Kunden c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GRUPPE NACH c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WO Rnk = 1
D. SELECT CustomerID, CustomerName, ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK () OVER (PARTITION BY c.CustomerID
ORDER BY COUNT (o.OrderAmount) ASC) AS Rnk
VOM Kunden c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GRUPPE NACH c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WO Rnk = 1
Answer: C