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NEW QUESTION: 1
WHICH COMMAND DO YOU ENTER ON ROUTER R6 SO THAT BGP SUPPORTS MULTIPLE
PROTOCOLS?
A. R6(confi-router)#bgp default ipv4-multicast
B. R6(config-router-af)#bgp additional-path install
C. R6(Config-router)#no address-family ipv6 unicast
D. R6(config-router)#no bgp default ipv4-multicast
Answer: C
NEW QUESTION: 2
Drag and Drop Question
Drag and drop the IPv4 network subnets from the left onto the correct usable host ranges on the right
Answer:
Explanation:
Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.
NEW QUESTION: 3
Which mechanism does GET VPN use to preseNeIP header information?
A. IPsec transpo mode
B. IPsec tunnel mode
C. MPLS
D. GRE
Answer: B
NEW QUESTION: 4
Which four factors can influence the rate of SQL apply on a logical standby database? (Choose four.)
A. the size of the shared pool
B. the number of PREPARER processes
C. the size of the undo tablespace on the logical standby database
D. the number of coordinator processes on the standby database instance
E. the number of APPLIER processes
F. the number of full table scans performed by SQL apply
Answer: A,B,E,F
Explanation:
Explanation/Reference:
Explanation:
B: If a table still does not have any unique index specified on the logical standby database, this may cause UPDATE statements to do full table scans on the logical standby database. You can remedy that by adding a unique index on the column on the logical standby database.
E: SQL Apply uses a collection of background processes to apply changes from the primary database to the logical standby database.
During apply processing:
* The ANALYZER process identifies dependencies between different transactions.
* The COORDINATOR process (LSP) assigns transactions to different appliers and coordinates among them to ensure that dependencies between transactions are honored.
* The APPLIER processes applies transactions to the logical standby database under the supervision of the coordinator process.
F: The PREPARER process is used during the log mining process, which is part of the SQL apply process.
D: The Shared Pool is used by the preparar and Builder proccesses.
Figure: SQL Apply Processing
Incorrect Answers:
C: There is only one coordinator process.
References: https://docs.oracle.com/cd/B28359_01/server.111/b28294/manage_ls.htm