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NEW QUESTION: 1
設計者は、ネストされたコンポーネントを含む複合ブループリントを作成したいが、デザインキャンバスのブループリントリストに必要なコンポーネントを表示できません。
この問題の考えられる理由は何ですか？
A. ネストされたブループリントはXaaSブループリントです。
B. ネストされたブループリントには、_deploymentNameカスタムプロパティが設定されていません。
C. ネストされたブループリントは公開されていません。
D. ネストされたブループリントは資格の一部ではありません。
Answer: B
NEW QUESTION: 2
You are creating a class library that will be used in a web application. You need to ensure that the class library assembly is strongly named. What should you do?
A. Use the EdmGen.exe command-line tool.
B. Use the csc.exe /target:Library option when building the application.
C. Use the xsd.exe command-line tool.
D. Use assembly attributes.
Answer: D
Explanation:
The Windows Software Development Kit (SDK) provides several ways to sign an assembly with a strong name:
*(A) Using assembly attributes to insert the strong name information in your code. You can use either the AssemblyKeyFileAttribute or the AssemblyKeyNameAttribute, depending on where the key file to be used is located.
*Using the Assembly Linker (Al.exe) provided by the Windows SDK.
*Using compiler options such /keyfile or /delaysign in C# and Visual Basic, or the /KEYFILE or /DELAYSIGN linker option in C++. (For information on delay signing, see Delay Signing an Assembly.)
NEW QUESTION: 3
How does a client app communicate with Hyperledger fabric chaincode (Smart Contracts)?
A. The app points to a node's IP address, then calls an invoke function on the chaincode address to start the write process
B. Client apps don't communicate with Hyperledger fabric directly, they must use Hyperledger Composer for the transmission
C. The app uses an SDK which invokes functionality on the chaincode which then announces the transaction to any peers required to endorse the transaction
D. The app uses Hyperledger Composer to communicate with CouchDB which in turn invokes chaincode functionality
Answer: C
NEW QUESTION: 4
展示を参照してください。すべてのルータインターフェイスが動作可能で、正しく設定されているとします。さらに、OSPFがルータR2で正しく設定されていると仮定します。 R1で設定されているデフォルトルートは、R2の動作にどのように影響しますか。
A. ルータR2に直接接続されていないネットワーク宛てのパケットは、R1にゲートウェイがないためにすぐにドロップされます。
B. ルータR2に直接接続されていないネットワーク宛てのパケットはただちに廃棄されます。
C. ルータR2のルーティングテーブルで参照されていないネットワーク宛てのパケットはすべてR1に転送されます。その後、R1はそのパケットをR2に返送し、ルーティングループが発生します。
D. ルータR1に直接接続されていないネットワーク宛てのパケットはすべて破棄されます。
E. ルータR2に直接接続されているネットワークは、172.16.100.0、172.16.100.128、および172.16.100.64のサブネットワークと通信できません。
Answer: C
Explanation:
First, notice that the more-specific routes will always be favored over less-specific routes regardless of the administrative distance set for a protocol. In this case, because we use OSPF for three networks (172.16.100.0 0.0.0.3, 172.16.100.64 0.0.0.63, 172.16.100.128 0.0.0.31) so the packets destined for these networks will not be affected by the default route. The default route configured on R1 "ip route 0.0.0.0 0.0.0.0 serial0/0 will send any packet whose destination network is not referenced in the routing table of router R1 to R2, it doesn't drop anything so answers A, B and C are not correct. D is not correct too because these routes are declared in R1 and the question says that "OSPF has been correctly configured on router R2, so network directly connected to router R2 can communicate with those three subnetworks. As said above, the default route configured on R1 will send any packet destined for a network that is not referenced in its routing table to R2; R2 in turn sends it to R1 because it is the only way and a routing loop will occur.