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NEW QUESTION: 1
Contoso。 Ltd.は、Azureで次のASP.NETワークロードをホストしています。
販売ソフトウェアのユーザーは、販売時に表示された在庫と実際の在庫との不一致を報告します。 2つのシステム間でトランザクションが発生すると、読み取りと書き込みに一貫性がなくなります。エラスティックトランザクションで受注作成と在庫ステータスの更新をカプセル化します。
トランザクションをサポートするには、コードとデータベースの変更を推奨する必要があります。
どのアクションをお勧めしますか？回答するには、回答エリアで適切なオプションを選択します。
注：それぞれの正しい選択には1ポイントの価値があります。
Answer:
Explanation:
NEW QUESTION: 2
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
NEW QUESTION: 3
ネットワークにcontoso.comという名前のActive Directoryドメインが含まれています。 ドメインには、Windows Server 2016を実行するServer1という名前のサーバーが含まれます。ユーザー1という名前のユーザーは、ローカルのAdministratorsグループのメンバーです。 Server1には、次のようにAppLockerルールが構成されています。
Rule1とRule2は、次の表のように構成されています。
User1がServer1でApp2.exeを実行できないことを確認します。
D：\\ Folder1 \\ Program.exeとD：\\ Folder2 \\ App2.exeのどちらを実行するのですか？ 2つを選択します。
A. D：\\ Folder2 \\ App2.exeをアップグレードすると、User1はD：\ App2.exeを実行できます。
B. Program.exeが更新された場合、User1はD：\\ Folder1 \\ Program.exeを実行できます。
C. D：\\ Folder2 \\ App2.exeを別のフォルダに移動すると、User1はD：\ App2.exeを実行できます。
D. D：\\ Folder2 \\ App2.exeの名前が変更された場合、User1はD：\ Folder2 \\ App2.exeを実行できます。
E. Program.exeの名前が変更された場合、User1はD：\\ Folder1 \\ Program.exeを実行できます。
F. Program.exeが別のフォルダに移動された場合、User1はD：\\ Folder1 \\ Program.exeを実行できます。
Answer: A,F
Explanation:
https://technet.microsoft.com/en-us/library/ee449492(v=ws.11).aspx
For "D:\\Folder1\\Program.exe", it is originally explicitly denied due to Rule1, when moving the "Program,exe" out of "D:\\Folder1\\", it does not match Rule1.
Assume that "Program.exe" is moved to "D:\\Folder2", it matches an Explicit Allow rule for group "BUILTIN
\\Administrators" which User1 is a member of, therefore A
is correct.
For "App2",exe, it matches a Explicit Deny rule using its File Hash (created File content), no matter where you move it to, or how you rename it, it would still match Rule2.
Only changing the file content of App2.exe would let it no longer match the explicit deny hash-based rule
"Rule2".
By upgrading its version and content, it will generate a new hash. so F is correct.