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NEW QUESTION: 1
You need to add a new lead scoring rule to a lead scoring model.
Which two scored field options allow you to define the new lead scoring rule? Each correct answer presents a complete solution.
A. Sales Rating
B. Event Session
C. Lead Score
D. Source Code
Answer: A,D
Explanation:
References:
https://www.microsoft.com/en-us/dynamics/marketing-customer-center/set-up-automatic- lead-scoring.aspx
NEW QUESTION: 2
Limitations of hybrid IDS will include:
A. All of the above
B. Platform availability
C. Deployment problems
D. System resource intensive
Answer: A
NEW QUESTION: 3
An online gaming site asked you if you can deploy a database that is a fast, highly scalable NoSQL database service in AWS for a new site that he wants to build. Which database should you recommend?
A. Amazon Redshift
B. Amazon RDS
C. Amazon SimpleDB
D. Amazon DynamoDB
Answer: D
Explanation:
Amazon DynamoDB is ideal for database applications that require very low latency and predictable performance at any scale but don't need complex querying capabilities like joins or transactions. Amazon DynamoDB is a fully-managed NoSQL database service that offers high performance, predictable throughput and low cost. It is easy to set up, operate, and scale. With Amazon DynamoDB, you can start small, specify the throughput and storage you need, and easily scale your capacity requirements on the fly. Amazon DynamoDB automatically partitions data over a number of servers to meet your request capacity. In addition, DynamoDB automatically replicates your data synchronously across multiple Availability Zones within an AWS Region to ensure high-availability and data durability.
https://aws.amazon.com/running_databases/#dynamodb_anchor
NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <deque>
#include <iostream>
#include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out<<val<<" "; } }; int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque<B> d1(t, t+10); sort(d1.begin(), d1.end()); deque<B>::iterator it = upper_bound(d1.begin(), d1.end(), B(4)); for_each(it, d1.end(), Out<B>(cout)); cout<<endl; return 0;
}
Program outputs:
A. 1 2 3 4 5
B. 1 2 3 4
C. 5 6 7 8 9 10
D. 6 7 8 9 10
E. 4 5 6 7 8 9 10
Answer: C