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NEW QUESTION: 1
Which two design recommendations are most appropriate when EIGRP is the data center core routing protocol? (Choose two.)
A. Advertise a default summary route into the data center core from the aggregation layer.
B. Use passive interfaces to ensure appropriate adjacencies.
C. Summarize data center subnets.
D. Adjust the default bandwidth value to ensure proper bandwidth on all links.
E. Tune the EIGRP timers to enable EIGRP to achieve quicker convergence.
Answer: B,C
Explanation:
"Here are some recommendations on EIGRP design for the data center core layer:
* Advertise a default summary route into the data center access layer with the ip summary- address eigrp interface command on the aggregation layer. * If other default routes exist in the network, such as from the Internet edge, you might need to filter them using distribute lists.
* Summarize the data center access layer subnets with the ip summary-address eigrp interface command from the aggregation layer.
* Use the passive-interface default command, and advertise only on the links that need to participate in the routing process using the no passive-interface interface command."

NEW QUESTION: 2
Frank has an archive named data-1-4.tar and he needs to examine the content of the archive. Which command will display the contents of the archive for Frank?
A. tar tvf data-1-4.tar
B. tar cvf data-1-4.tar
C. tar uvf data-1-4.tar
D. tar rvf data-1-4.tar
E. tar xvf data-1-4.tar
Answer: A

NEW QUESTION: 3
A portfolio manager is evaluating investments in mortgage securities as part of a portfolio to fund long term liabilities. If she wants to minimize prepayment risk in her portfolio she is most likely to invest in:
A. Investment evaluation
B. Collateralized mortgage obligations
C. Mortgage loans
D. Mortgage pass through securities
Answer: B

NEW QUESTION: 4
Given the following SAS statement:
%let idcode = Prod567;
Which one of the following statements stores the value 567 in the macro variable CODENUM?
A. %let codenum = %substr(&idcode,%length(&idcode)-2);
B. %let codenum = %substr(&idcode,%length(&idcode)-3);
C. %let codenum = substr(&idcode,length(&idcode)-2);
D. %let codenum = substr(&idcode,length(&idcode)-3);
Answer: A

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