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NEW QUESTION: 1
Which of the following is the BEST means of ensuring resource utilization remains even across the hosts?
A. Resource pooling
B. VM affinity
C. Dynamic VM placement
D. VM high availability
Answer: C
NEW QUESTION: 2
Which of the following options best describes what the configure "Shared User Hosts" feature that is found under Appliance Manager's Setup > FTP > Caching Behavior is used for?
A. a subset of FTP servers that can be bound to a shared virtual IP address in order to increase overall caching efficiency
B. a subset of FTP servers that will be acceleratedbytheNetCache appliance
C. FTP servers from which fetched objects will be cached and served without a user-specific key requirement in order to increase the cachingefficiency
D. a shared IP address that all requesting clients will use to circumvent any authentication or user-specific key requirements on the backend FTP servers
Answer: C
NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to retrieve the students who scored the highest marks for each subject along with the marks.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
C. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
D. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
E. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
F. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
G. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
H. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
Answer: G
NEW QUESTION: 4
Refer to the exhibit.
Statements A, B, C, and D of ACL 10 have been entered in the shown order and applied to interface E0 inbound, to
prevent all hosts (except those whose addresses are the first and last IP of subnet 172.21.1.128/28) from accessing the
network. But as is, the ACL does not restrict anyone from the network. How can the ACL statements be re-arranged so
that the system works as intended?
A. CDBA
B. DBAC
C. ACDB
D. BADC
Answer: A
Explanation:
Routers go line by line through an access list until a match is found and then will not look any further, even if a more
specific of better match is found later on in the access list. So, it it best to begin with the most specific entries first, in this cast the two hosts in line C and D.
Then, include the subnet (B) and then finally the rest of the traffic (A).