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NEW QUESTION: 1
Given the raw data file EMPLOYEE.TXT:
The following SAS program is submitted:
What value does the variable idnum contain when the name of the employee is "Ruth"?
A. 0
B. 1
C. 2
D. 3
Answer: C
NEW QUESTION: 2
Welches der folgenden Verfahren wäre die BESTE Zugangskontrolle?
A. Der Dateneigentümer autorisiert den Zugriff offiziell und ein Administrator implementiert die Benutzerberechtigungstabellen.
B. Autorisiertes Personal implementiert die Benutzerberechtigungstabellen und der Dateneigentümer genehmigt sie.
C. Der Dateneigentümer erstellt und aktualisiert die Benutzerberechtigungstabellen.
D. Der Dateneigentümer und ein IS-Manager erstellen und aktualisieren gemeinsam die Benutzerberechtigungstabellen.
Answer: A
Explanation:
Erläuterung:
Der Dateneigentümer hat das Privileg und die Verantwortung für die formelle Einrichtung der Zugriffsrechte. Ein IS-Administrator sollte dann Benutzerberechtigungstabellen implementieren oder aktualisieren. Wahl B ändert die gewünschte Reihenfolge. Wahl C ist kein formelles Verfahren zur Autorisierung des Zugriffs.
NEW QUESTION: 3
ネットワークにcontoso.comという名前のActive Directoryドメインが含まれています。 ドメインには、複数のアプリケーションを実行する複数のサーバーが含まれています。 ドメインユーザーアカウントは、サーバーへのアクセス要求を認証するために使用されます。
NTLMがサーバーへの認証に使用されないようにする予定です。
ドメインのNTLM認証イベントを監査し始めます。 すべてのNTLM認証イベントを表示し、NTLMを使用して認証するアプリケーションを特定する必要があります。
どのコンピュータでイベントログを確認し、どのログを確認する必要がありますか。 回答するには、回答領域で適切なオプションを選択します。
Answer:
Explanation:
Explanation
Do not confuse this with event ID 4776 recorded on domain controller's security event log!!!This question asks for implementing NTLM auditing when domain clients is connecting to memberservers! See below for further information.https://docs.microsoft.com/en-us/windows/device-security/security-policy-settings/net work-security-restrict-ntlmaudit-ntlm-authentication-in-this-domainVia lab testing, most of the NTLM audit logs are created on Windows 10 clients, except that you use WindowsServer 2016 OS as clients (but this is unusual)
NEW QUESTION: 4
On the basis of the network provided in the exhibit, all routers are configured to run EIGRP on all links. If the link between R1 and R2 fails, what is the maximum number of queries R3 will receive for 192.168.1.0/24, assuming that all the packets sent during convergence are transmitted once (there are no dropped or retransmitted packets)?
A. R3 will not receive any queries from R2, because there are no alternate paths for 192.168.1.0/24.
B. R3 will receive up to four queries for 192.168.1.0/24, one each from R2, R4, R5, and R6.
C. R3 will receive one query for 192.168.1.0/24, since the remote routers, R4, R5, and R6, are natural stubs in EIGRP.
D. R3 will receive up eight queries for 192.168.1.0/24, one from R2, two from R4, three from R5, and four from R6.
Answer: B
Explanation:
When EIGRP loses its successor or primary route, EIGRP immediately tries to reconverge by looking at its topology table to see if any feasible successors are available. If a feasible successor is available, EIGRP immediately promotes the feasible successor to a successor and informs its neighbors about the change. The feasible successor then becomes the next hop for EIGRP to forward the packets to the destination. The process by which EIGRP converges locally and does not involve other routers in the convergence process is called local computation. This also saves CPU power because all the feasible successors are already chosen before the primary route failures. If the primary route is not available for some reason, the preselected feasible successor immediately takes over as the primary route.
Now, if the primary route goes away and no feasible successors are available, the router goes into diffused computation. In diffused computation, the router sends query packets to all its neighbors asking for the lost route, and the router goes into Active state. If neighboring routers have information about the lost route, they reply to the querying router. If neighboring routers do not have information about the lost route, they send queries to all their neighbors. If the neighboring router does not have an alternate route and doesn't have any other neighbors, it sends a reply packet back to the router with a metric set to infinity, indicating that it, too, doesn't have an alternate route available. The querying router waits for all the replies from all its neighbors and then chooses the neighbor with the best metric in its replies as the next hop to forward packets.