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NEW QUESTION: 1
Which address block is reserved for locally assigned unique local addresses?
A. FD00::/8
B. FB00::/8
C. 2001::/32
D. 2002::/16
Answer: A
Explanation:
The address block fc00::/7 is divided into two /8 groups:
+ The block fc00::/8 has not been defined yet. It has been proposed to be managed by an allocation authority, but this has not gained acceptance in the IETF
+ The block fd00::/8 is defined for /48 prefixes, formed by setting the 40 least-significant bits of the prefix to a randomly generated bit string Prefixes in the fd00::/8 range have similar properties as those of the IPv4 private address ranges:
+ They are not allocated by an address registry and may be used in networks by anyone without outside involvement.
+ They are not guaranteed to be globally unique.
+ Reverse Domain Name System (DNS) entries (under ip6.arpa) for fd00::/8 ULAs cannot be delegated in the global DNS.
Source:
https://en.wikipedia.org/wiki/Unique_local_address

NEW QUESTION: 2
A loan portfolio's full notional value is $100, and its value in a worst case scenario at the 99% level of confidence is $65. Expected losses on the portfolio are estimated at 10%. What is the level of economic capital required to cushion unexpected losses?
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
Explanation
Expected value = $90 ($100 - 10%)
Value at 99% confidence level = $65
Therefore economic capital required at this level of confidence = $90 - $65 = $25.
Choice 'a' is the correct answer, the other choices are not.
(We can also look at it this way as explained in section III.B.6.2.2 of the handbook: Economic capital is designed to absorb unexpected losses, which are equal to total losses at a given confidence level minus expected losses. (Expected losses are to be covered by credit reserves). Total losses are $100-$65=$35, and expected losses are 10%*$100=$10, therefore economic capital should be $35-$10=$25.)

NEW QUESTION: 3
Which of the following measure describes the symmetry of a statistical distribution?
A. Skewness
B. Mean
C. Standard deviation
D. Kurtosis
Answer: A

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