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NEW QUESTION: 1
Block size is calculated by the following formula.
A. Number of stored dense dimension members multiplied together times 8 bytes
B. Number of total dense dimension members multiplied together times 8 bytes
C. Number of total sparse dimension members multiplied together times 8 bytes
D. Number of stored sparse dimension members multiplied together times 8 bytes
Answer: A
Explanation:
Explanation/Reference:
Data block size is determined by the amount of data in particular combination of dense dimensions. For ex:
when you change the dense or sparse configuration of one or more dimensions in the database, the data block size changes. Data block size is 8n bytes, where n is the number of cells that exist (ie. Stored, not total) for that combination of dense dimensions.Note: Optimal range is 8 to 100 kb We need to multiple the stored (not the total) members of the dense dimensions with 8 to calculate the block size.
NEW QUESTION: 2
Which of the following methods of evaluating capital projects incorporate an explicit discount rate into the equation?
A. Internal Rate of Return, Modified Internal Rate of Return
B. Discounted Payback Period, Net Present Value, Internal Rate of Return
C. Discounted Payback Period, Net Present Value, Modified Internal Rate of Return
D. Discounted Payback Period, Net Present Value, Payback Period
E. Net Present Value, Payback Period
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Of the methods for evaluating capital projects, the Net Present Value, Modified Internal Rate of Return, and Discounted Payback Period Methods incorporate an explicit discount rate into their equations. This discount rate is often referred to as the "cost of capital" for the project being examined. Remember that the Internal Rate of Return equation does not involve the incorporation of an explicit discount rate,rather solves to find that rate which equates the present value of a project's cash inflows with that of its cash outflows.
Additionally, the "Payback Period" method does not involve an explicit discount rate, rather fails to incorporate any form of discounting into its calculation. The Payback Period is an overtly simplistic method, and as such, the figures produced by this method should be viewed with a degree of caution.
NEW QUESTION: 3
Scenario: A Citrix Architect needs to design a new XenApp and XenDesktop environment.
The architect has identified printing requirements for certain user groups and locations, as shown in the Exhibit.
Click the Exhibit button to view the requirements.
Currently, no printer settings or policies have been configured, and as such, the environment is using default settings. Universal Print Server will NOT be used in this design.
Which two settings should the architect configure to allow the Executives group to achieve the desired print behavior and to ensure their print jobs are optimally routed? (Choose two.)
A. Set Auto-create Client Printers policy to auto-create local printers only
B. Set Direct connections to print servers policy to Disabled
C. Configure Default Printers policy
D. Set Direct connections to print servers policy to Enabled
E. Enable Auto-create PDF Universal Printer policy
F. Set Auto-create Client Printers policy to auto-create all client printers
G. Configure Session Printers policy
Answer: D,F
Explanation:
Direct connections to print servers
This setting enables or disables direct connections from the virtual desktop or server hosting applications to a print server for client printers hosted on an accessible network share.
By default, direct connections are enabled.
Enable direct connections if the network print server is not across a WAN from the virtual desktop or server hosting applications. Direct communication results in faster printing if the network print server and the virtual desktop or server hosting applications are on the same LAN.
Disable direct connections if the network is across a WAN or has substantial latency or limited bandwidth. Print jobs are routed through the user device where they are redirected to the network print server. Data sent to the user device is compressed, so less bandwidth is consumed as the data travels across the WAN.
If two network printers have the same name, the printer on the same network as the user device is used.
https://docs.citrix.com/en-us/xenapp-and-xendesktop/7-15-ltsr/policies/reference/ica-policy-settings/printing-policy-settings/client-printers-policy-settings.html Note:
G: Why?
A: Set Auto-create Client Printers policy to auto-create local printers only. No, because we want all client printers which will include local (non-network) and network printers.
E: Configure Session Printers policy - No, because we will have to list all the network printers to be auto- created.
NEW QUESTION: 4
Which of the following is NOT a key recovery method?
A. A message is encrypted with a session key. The session key, in turn, is broken into parts and each part is encrypted with the public key of a different trustee agent. The encrypted parts of the session key
are sent along with the encrypted message. The trustees, when
authorized, can then decrypt their portion of the session key and
provide their respective parts of the session key to a central agent.
The central agent can then decrypt the message by reconstructing
the session key from the individual components.
B. A message is encrypted with a session key and the session key is, in turn, encrypted with the public key of a trustee agent. The encrypted session key is sent along with the encrypted message. The
trustee, when authorized, can then decrypt the message by recovering
the session key with the trustee's private key.
C. A secret key or a private key is broken into a number of parts and
each part is deposited with a trustee agent. The agents can then
provide their parts of the key to a central authority, when presented
with appropriate authorization. The key can then be reconstructed
and used to decrypt messages encrypted with that key.
D. A message is encrypted with a session key and the session key is, in turn, encrypted with the private key of a trustee agent. The encrypted session key is sent along with the encrypted message. The
trustee, when authorized, can then decrypt the message by
recovering the session key with the trustee's public key.
Answer: D
Explanation:
Encrypting parts of the session key with the private keys of the
trustee agents provides no security for the message since the
message can be decrypted by recovering the key components of
the session key using the public keys of the respective agents. These
public keys are available to anyone.
The other answers are valid means of recovering keys, since key recovery refers to permitting access to encrypted messages under predefined circumstances.
Two of these answers are also called key encapsulation since the session key is encapsulated in the public keys of the trustee agents and, therefore, can be decrypted only by these trustee agents with their
private keys.