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NEW QUESTION: 1
Which option is not an example of a level-based measure?
A. Employee Salary
B. Brand Cost
C. Sales
D. Regional Revenue
Answer: B
Explanation:
Note 1: A level-based measure is a column whose values are always calculated to a specific level
of aggregation.
The calculation of this measure is independent of the query grain and used always the
aggregation grain of the logical column.
Level-based measures allow :
*to return data at multiple levels of aggregation (the query grain and the level-based column grain)
with one single query
*to create share measures (percentage), that are calculated by taking some measure and dividing
it by a level-based measure. For example, you can divide salesperson revenue by regional
revenue to calculate the share of the regional revenue each salesperson generates.
Note 2: To create a level based measure as the amount sold by region, you can:
*make a copy of the Amount Sold logical column
*and then
/ drag the logical column into its hierarchy level
/ or set the aggregation grain in the level tab of the logical column property.

NEW QUESTION: 2
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: D
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1

NEW QUESTION: 3
What is true about Cisco Discovery Protocol ?
A. it is physical and data link layer protocol
B. it is network layer protocol
C. it is Cisco proprietary protocol
D. it discovers the routers, switches and gateways.
Answer: C

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