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NEW QUESTION: 1
During an audit of a mission-critical system hosted in an outsourced data center, an IS auditor discovers that contracted routine maintenance for the alternate power generator was not performed. Which of the following should be the auditor's MAIN concern?
A. Fraudulent behavior by the outsourcer charging for work not performed
B. High repair costs if faulty generator parts are not detected in a timely manner
C. Loss of warranty due to lack of system maintenance
D. Failure of the alternate power generator during a power outage
Answer: D
NEW QUESTION: 2
Which two options can be used to monitor PDQ resources? (Choose two.)
A. SET EXPLAIN output.
B. onstat -g ath.
C. onstat -D.
D. onstat -l.
E. onstat -p.
Answer: A,B
NEW QUESTION: 3
Which of the following uses protection profiles and security targets?
A. TCSEC
B. CTCPEC
C. International Standard 15408
D. ITSEC
Answer: C
Explanation:
"For historical and continuity purposes, ISO has accepted the continued use of the term "Common Criteria" (CC) within this document, while recognizing the official ISO name for the new IS 15408 is "Evaluation Criteria for Information Technology Security." Pg. 552 Krutz: The CISSP Prep Guide: Gold Edition
"The Common Criteria define a Protection Profile (PP), which is an implementation-independent specification of the security requirements and protections of a product that could be built. The Common Criteria terminology for the degree of examination of the product to be tested is the Evaluation Assurance Level (EAL). EALs range from EA1 (functional testing) to EA7 (detailed testing and formal design verification). The Common Criteria TOE refers to the product to be tested. A Security Target (ST) is a listing of the security claims for a particular IT security product. Also, the Common Criteria describe an intermediate grouping of security requirement components as a package." Pg. 266-267 Krutz: The CISSP Prep Guide: Gold Edition
NEW QUESTION: 4
The following data is some of the output produced by a program. Which program produced this output?
strftime (" Thu", 1024, "%a", 0xb7f64380) =4 fwrite ("Thu", 3, 1, 0xb7f614e0) =1 fputc (' ', 0xb7f614e0) =32 strftime (" Feb", 1024, " %b", 0xb7f64380) =4 fwrite ("Feb", 3, 1, 0xb7f614e0) =1 fputc (' ', 0xb7f614e0) =32 fwrite ("19", 2, 1, 0xb7f614e0) =1
A. time
B. lsof
C. nm
D. 1trace
E. strace
Answer: D