Questions and Answers: 166
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NEW QUESTION: 1
本社でオンプレミスのASP.NET Web APIをホストします。 Web APIは、Azure Relayサービスを使用して会社の支社で実行されているアプリケーションによって使用されます。アプリケーションのすべてのユーザーが同じAzure Active Directory（Azure AD）上にあります。
アプリケーションがWeb APIを使用できるようにする必要があります。
あなたは何をするべきか？
A. 送信者と受信者という名前の別々のADグループを作成します。リレーネームスペースのアクセス制御（IAM）で、送信者にReaderの役割を割り当て、受信者にReaderの役割を割り当てます。
B. 送信アクセス許可と受信アクセス許可用に共有アクセスポリシーを作成します。
C. ネームスペース用の共有アクセスポリシーを作成します。 Web APIで接続文字列を使用し、コンシューマアプリケーションでは別の接続文字列を使用します。
D. SenderとReceiverという名前の専用のAzure AD IDを作成します。送信者にAzure AD IDリーダーの役割を割り当てます。受信者にAzure AD IDリーダーの役割を割り当てます。それぞれのIDを使用するようにアプリケーションを構成してください。
Answer: C
Explanation:
説明/参照：
参考文献：
https://docs.microsoft.com/ja-jp/azure/service-bus-relay/relay-authentication-and-authorization質問セット1
NEW QUESTION: 2
Your company develops a bot that uses QnA Maker knowledge bases and Language Understanding Intelligence Services (LUIS). You create the QnA Maker service, knowledge bases, and the LUIS app.
The bot application must use LUIS to determine which QnA Maker knowledge base to use.
You need to integrate LUIS with the QnA Maker knowledge bases and maximize the effectiveness for selecting the QnA Maker knowledge bases before testing the bot.
Which four actions should you perform in sequence? To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.
Answer:
Explanation:
NEW QUESTION: 3
Refer to the exhibit. What does the return code 3 represent in this output?
A. The return code is reserved.
B. The mapping of the replying router for the FEC is different.
C. The packet is label-switched at stack depth.
D. The replying router was the proper egress for the FEC.
E. The upstream index is unknown.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Return Codes
The Return Code is set to zero by the sender. The receiver can set it to one of the values listed below. The notation <RSC> refers to the Return Subcode. This field is filled in with the stack-depth for those codes that specify that. For all other codes, the Return Subcode MUST be set to zero.
Value Meaning
----- -------
0
1
2
3
4
No return code
Malformed echo request received
One or more of the TLVs was not understood
Replying router is an egress for the FEC at stack- depth <RSC>
Replying router has no mapping for the FEC at stack- depth <RSC>
Reference: https://www.ietf.org/rfc/rfc4379.txt
NEW QUESTION: 4
あなたはモバイルアプリケーションをデザインする会社のために働いています。彼らはプレーヤーの記録が彼らの異なるゲームに割り当てられるサーバーを維持します。追跡システムは新しく、開発中です。
アプリケーションはEntity Frameworkを使用してAzureデータベースに接続します。データベースには、PlayerテーブルとGameテーブルがあります。
プレーヤーを追加するとき、コードは新しいプレーヤーレコードを挿入し、既存のゲームレコードと新しいプレーヤーレコードの間の関係を追加する必要があります。
アプリケーションは正しいgameIdとplayerIdを指定してCreatePlayerWithGameを呼び出し、プロセスを開始します。
（行番号は参照用にのみ含まれています。）
以下の各ステートメントについて、そのステートメントが正しい場合は「はい」を選択してください。そうでなければ、いいえを選択します。
注：それぞれ正しい選択は1ポイントの価値があります。
Answer:
Explanation:
Explanation
Many-to-many relationships without an entity class to represent the join table are not yet supported. However,
you can represent a many-to-many relationship by including an entity class for the join table and mapping two
separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}