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NEW QUESTION: 1
PKIは通常、キーを安全に投影するために次の暗号化方法のうちどれを使用しますか？
A. 楕円曲線
B. 非対称
C. 難読化
D. デジタル署名
Answer: B

NEW QUESTION: 2
Which of the following types of attack works by taking advantage of the unenforced and unchecked assumptions the system makes about its inputs?
A. None of the choices.
B. code injection
C. integer overflow
D. command injection
E. format string vulnerabilities
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Code injection is a technique to introduce code into a computer program or system by taking advantage of the unenforced and unchecked assumptions the system makes about its inputs.

NEW QUESTION: 3
A company pays commission based on the source of the transaction and the margin on the transaction.
If the source is 'ABC' and margin is between 0 and 10 percent, the rate should be 1.5 percent.
If the source is 'ABC' and margin is 10 percent and above, the rate should be 3 percent.
If the source is 'XYZ' and margin is between 0 and 10 percent, the rata should be 2 percent.
If the source is 'XYZ' and margin is 10 percent and above, the rate should be 4 percent.
Which two procedures can you use to set this up?


A. Option B
B. Option C
C. Option A
D. Option D
E. Option E
Answer: B,E

NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
Answer: C