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NEW QUESTION: 1
ネットワークにcontoso.comという名前のActive Directoryドメインが含まれています。 ドメインには、複数のアプリケーションを実行する複数のサーバーが含まれています。 ドメインユーザーアカウントは、サーバーへのアクセス要求を認証するために使用されます。
NTLMがサーバーへの認証に使用されないようにする予定です。
ドメインのNTLM認証イベントを監査し始めます。 すべてのNTLM認証イベントを表示し、NTLMを使用して認証するアプリケーションを特定する必要があります。
どのコンピュータでイベントログを確認し、どのログを確認する必要がありますか。 回答するには、回答領域で適切なオプションを選択します。

Answer:
Explanation:

Explanation

Do not confuse this with event ID 4776 recorded on domain controller's security event log!!!This question asks for implementing NTLM auditing when domain clients is connecting to memberservers! See below for further information.https://docs.microsoft.com/en-us/windows/device-security/security-policy-settings/net work-security-restrict-ntlmaudit-ntlm-authentication-in-this-domainVia lab testing, most of the NTLM audit logs are created on Windows 10 clients, except that you use WindowsServer 2016 OS as clients (but this is unusual)

NEW QUESTION: 2
HOTSPOT
You are maintaining statistics for a database table named tbiTransaction. The table contains more than
1 0 million records.
You need to create a stored procedure that meets the following requirements:
-On weekdays, update statistics for a sample of the total number of records in the table.
-On weekends, update statistics by sampling all rows in the table.
A maintenance task will call this stored procedure daily.
How should you complete the stored procedure? To answer, select the appropriate Transact-SOL
segments in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

NEW QUESTION: 3
The test method above calls an @future method that increments the Number_of_Times_Viewed__c value. The assertion is failing because the Number_of_Times_Viewed__c equals 0. What is the optimal way to fix this?
A. Add Test.startTest() before and Test.stopTest() after insert acct
B. Add Test.startTest() before and Test.stopTest() after AuditUtil.incrementViewed.
C. Change the initialization to acct.Number_Of_Times_Viewed__c = 1.
D. Change the assertion to System.assertEquals(0, acctAfter.Number_Of_Times_Viewed__c).
Answer: C